- ✅ Ticket 1.1: Estructura Clean Architecture en backend - ✅ Ticket 1.2: Schemas Zod compartidos - ✅ Ticket 1.3: Refactorización drugs.ts (1362 → 8 archivos modulares) - ✅ Ticket 1.4: Refactorización procedures.ts (3583 → 6 archivos modulares) - ✅ Ticket 1.5: Eliminación de duplicidades (~50 líneas) Cambios principales: - Creada estructura Clean Architecture en backend/src/ - Schemas Zod compartidos en backend/src/shared/schemas/ - Refactorización modular de drugs y procedures - Utilidades genéricas en src/utils/ (filter, validation) - Eliminados scripts obsoletos y documentación antigua - Corregidos errores: QueryClient, import test-error-handling - Build verificado y funcionando correctamente
62 lines
1.7 KiB
JavaScript
62 lines
1.7 KiB
JavaScript
module.exports = exports = abbrev.abbrev = abbrev
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abbrev.monkeyPatch = monkeyPatch
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function monkeyPatch () {
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Object.defineProperty(Array.prototype, 'abbrev', {
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value: function () { return abbrev(this) },
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enumerable: false, configurable: true, writable: true
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})
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Object.defineProperty(Object.prototype, 'abbrev', {
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value: function () { return abbrev(Object.keys(this)) },
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enumerable: false, configurable: true, writable: true
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})
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}
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function abbrev (list) {
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if (arguments.length !== 1 || !Array.isArray(list)) {
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list = Array.prototype.slice.call(arguments, 0)
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}
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for (var i = 0, l = list.length, args = [] ; i < l ; i ++) {
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args[i] = typeof list[i] === "string" ? list[i] : String(list[i])
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}
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// sort them lexicographically, so that they're next to their nearest kin
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args = args.sort(lexSort)
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// walk through each, seeing how much it has in common with the next and previous
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var abbrevs = {}
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, prev = ""
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for (var i = 0, l = args.length ; i < l ; i ++) {
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var current = args[i]
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, next = args[i + 1] || ""
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, nextMatches = true
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, prevMatches = true
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if (current === next) continue
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for (var j = 0, cl = current.length ; j < cl ; j ++) {
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var curChar = current.charAt(j)
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nextMatches = nextMatches && curChar === next.charAt(j)
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prevMatches = prevMatches && curChar === prev.charAt(j)
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if (!nextMatches && !prevMatches) {
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j ++
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break
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}
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}
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prev = current
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if (j === cl) {
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abbrevs[current] = current
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continue
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}
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for (var a = current.substr(0, j) ; j <= cl ; j ++) {
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abbrevs[a] = current
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a += current.charAt(j)
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}
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}
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return abbrevs
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}
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function lexSort (a, b) {
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return a === b ? 0 : a > b ? 1 : -1
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}
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